Simple technique for preparing any strength volumetric solution,.
Today’s topic
Molarity of Concentrated Reagents
Hello
friends
Please find
below details, for preparing normal or molar solution using the concentrated
reagents.
By
using this technique sure you can prepare any strength volumetric solution, without any
reference. Just remember the simple equation and normality strength of the
concentrated reagents. Preparation details provided below the table
DILUTIONS TO MAKE A 1 MOLAR/NORMAL
SOLUTION
|
Concentrated Reagents |
Density |
Molarity |
Normality |
Volume (mL) |
|
|
1M |
1N |
||||
|
Acetic acid 99.5% |
1.05 |
17.4 |
17.4 |
57.5 |
57.5 |
|
Ammonia 35% |
0.880 |
18.1 |
18.1 |
55.3 |
55.3 |
|
Ammonia 25% |
0.910 |
13.4 |
13.4 |
74.6 |
74.6 |
|
Hydrochloric acid 36% |
1.18 |
11.65 |
11.65 |
85.8 |
85.8 |
|
Hydrochloric acid 32% |
1.16 |
10.2 |
10.2 |
98.0 |
98.0 |
|
Hydrofluoric acid 40% |
1.13 |
22.6 |
22.6 |
44.2 |
44.2 |
|
Nitric acid 70% |
1.42 |
15.8 |
15.8 |
63.3 |
63.3 |
|
Perchloric acid 60% |
1.54 |
9.2 |
9.2 |
108.7 |
108.7 |
|
Perchloric acid 70% |
1.67 |
11.6 |
11.6 |
86.2 |
86.2 |
|
Orthophosphoric acid 85% |
1.7 |
15.2 |
45.6 |
65.8 |
21.9 |
|
Sodium hydroxide 47% |
1.5 |
17.6 |
17.6 |
56.7 |
56.7 |
|
Sulfuric acid 98% |
1.84 |
18.4 |
36.8 |
54.3 |
27.2 |
·
For preparing 1Normal or 1Molar solution using the
concentrated reagent refers below equation.
·
The, strength of concentrated reagent tabulated in the
above table with its purity and density.
·
If Normal or Molar solution to be prepared by weighing
the concentrated reagent, in that case do not forgot to apply density
correction.
CONSIDER
EXAMPLE OF ACETIC ACID
Using 99.5% purity Acetic acid reagent, Preparation details for 1Ltr (1000mL) of normal/ Molar strength solution mentioned below.
i)
If purity of Acetic acid is 99.5% the Normality is 17.4
Equation:
N1 x V1 = N2 x
V2
N1 : Normality
of concentrated Reagent. (Concentrated acetic acid 17.4N)
V1 : Volume of
concentrated reagent required to prepare 1Ltr or 1000mL of 1N or
1M strength solution (To be calculated)
N2 : 1N Strength solution to be prepared
V2 : Total volume of 1N strength
solution required.
17.4 x V1 = 1N x 1000
=
1N x 1000
17.4
V1
= 57.47 ~ 57.5 mL
Inference:
57.5mL of
Acetic acid to be mixed and diluted to 1000mL with the water to prepare
1N/1M Strength of acetic acid
Acetic acid is mono basic acid. Hence the molarity and
normality for the Acetic acid are same.
CONSIDER
EXAMPLE OF HYDROCHLORIC ACID
Using 36% purity HCl reagent, Preparation details for 1Ltr (1000mL) of normal/ Molar strength solution mentioned below.
Note
i)
If purity of HCl is 36% the Normality is 11.65
N1 x V1 = N2 x
V2
N1 : Normality of concentrated Reagent. (Concentrated
HCl 11.65N)
V1 : Volume of concentrated reagent required to prepare
1Ltr or 1000mL of 1N or
1M strength solution
(To be calculated)
N2 : 1N Strength solution to be prepared
V2 : Total volume of
1N strength solution required.
11.65 x
V1 = 1N x 1000
=
1N x 1000
11.65
V1
= 85.83 ~ 85.8 mL
The normality and molarity for the hydrochloric acid are
same.
If
purity of HCl is 32% the Normality is 10.2
N1 x V1 = N2 x
V2
N1 : Normality
of concentrated Reagent. (Concentrated HCl 10.2N)
V1 : Volume of
concentrated reagent required to prepare 1Ltr or 1000mL of 1N or
1M strength solution (To be calculated)
N2 : 1N Strength solution to be prepared
V2 : Total volume of 1N strength
solution required.
10.2 x
V1 = 1N x 1000
=
1N x 1000
10.2
V1
= 98.03 ~ 98.0 mL
Inference:
Hydrochloric
acid is mono basic acid. Hence the normality and molarity for the hydrochloric
acid are same.
CONSIDER
EXAMPLE OF SULPHURIC ACID
Using 98%
purity Sulphuric acid reagent, Preparation details for 1Ltr (1000mL) of normal/
Molar strength solution.
N1 x V1 = N2 x
V2
N1 : Normality
of concentrated Reagent. (Concentrated acetic acid 36.8N)
V1 : Volume of
concentrated reagent required to prepare 1Ltr or 1000mL of 1N or
1M strength solution
(To be calculated)
N2 : 1N Strength solution to be prepared
V2 : Total volume of 1N strength
solution required.
17.4 x
V1 = 1M x 1000
=
1N x 1000
36.8
V1
= 27.17 ~ 27.2 mL
Inference:
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Very useful knowledge. Many Thanks 🙏
ReplyDeletegood information and very useful.. thank you sir...
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